What two number would times eachother to equal -6 and add together to equal 1

Answer 1

To find two numbers that, when multiplied, give -6 and when added, give 1, we can set up a system of equations.

Let's assume the two numbers are x and y.

According to the given conditions, we have the following equations:
xy = -6 (equation 1)
x + y = 1 (equation 2)

Now, we can solve this system of equations for x and y.

From equation 2, we can express x in terms of y:
x = 1 - y (equation 3)

Substituting equation 3 into equation 1, we have:
(1 - y)y = -6

Expanding the equation:
y - y^2 = -6

Rearranging the equation:
y^2 - y + 6 = 0

This quadratic equation does not have real solutions. Therefore, there are no two real numbers that satisfy both conditions: multiplying to get -6 and adding to get 1.