To find the value of \( v76 \) (which might refer to the 76th term in a sequence or some specific numerical context), let's assume you are asking for the square root of 76, or possibly an estimate based on perfect squares.
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Finding the Perfect Squares:
- The perfect squares around 76 are \( 64 \) (which is \( 8^2 \)) and \( 81 \) (which is \( 9^2 \)).
- Therefore, we can conclude: \[ 8 < \sqrt{76} < 9 \]
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Answering the Questions:
- Question Blank 1 of 4: v76 is greater than the square root of the perfect square \( 64 \).
- Question Blank 2 of 4: v76 is less than the square root of the perfect square \( 81 \).
- Question Blank 3 of 4: The value \( 76 \) is closer to \( 81 \) than to \( 64 \) (since 76 is significantly closer to 81).
- Question Blank 4 of 4: An estimate for \( v76 \) is approximately \( 8.7 \) (since \( \sqrt{76} \approx 8.717 \)).
Summary of Answers:
- 8
- 9
- 9
- Approximately 8.7