What the base b1 of an Isosceles trapezoid if b2=57ft,h=17ft6inches and both legs are 23ft? or the formula for the solution?thank you.

Answer 1

At each side of the trapezoid is a righ triangle with height 17.5 and hypotenuse 23. the base leg a is given by

a^2 + 17.5^2 = 23^2
so, a = 14.92

There are two of these triangles, so their combined base legs make 29.84

Subtract that from 57 and we see that the inner rectangle has height 17.5 and width 27.16 top and bottom. That's the upper base of the trapezoid.

Answer 2

thanks