What subatomic particles are in magnesium-27 if its charge is 2+? 12 p+, 15 n0, 7 e-

12 p+, 15 n0, 10 e-
12 p+, 15 n0, 11 e-
12 p+, 15 n0, 12 e-

1 answer

To determine the subatomic particles in magnesium-27 (\(^{27}_{12}\text{Mg}\)) with a charge of 2+, let's start with the basic properties of magnesium-27.

  1. Mass Number (A): The mass number is 27, which is the total number of protons and neutrons in the nucleus.
  2. Atomic Number (Z): The atomic number of magnesium is 12, which is the number of protons (\(p^+\)) in the nucleus.

From this information, we can deduce the following:

  • Protons: There are 12 protons.

  • Neutrons: To find the number of neutrons (\(n^0\)), we use the formula: \[ \text{Neutrons} = A - Z = 27 - 12 = 15 \] So, there are 15 neutrons.

  • Electrons: For a neutral magnesium atom, it would also have 12 electrons (\(e^-\)). However, since the charge of this ion is 2+, this means it has lost 2 electrons: \[ \text{Electrons} = 12 - 2 = 10 \] Therefore, there are 10 electrons in the ion with a charge of 2+.

So, the subatomic particles in magnesium-27 with a charge of 2+ are:

  • 12 protons
  • 15 neutrons
  • 10 electrons

The correct option from your list is: 12 p+, 15 n0, 10 e-.