what sould be the angular speed with which the earth have to rotate on its axis so that a person on the equator would weight 3/5th as much as present..??

2 answers

Solve this equation for Earth angular speed in radians per second:

Mg - M Rw^2 = 0.6 M g
Cancel out the M's

0.4 g = R w^2
w = sqrt(0.4g/R)

Use R = 6371*10^3 m
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