Solve this equation for Earth angular speed in radians per second:
Mg - M Rw^2 = 0.6 M g
Cancel out the M's
0.4 g = R w^2
w = sqrt(0.4g/R)
Use R = 6371*10^3 m
what sould be the angular speed with which the earth have to rotate on its axis so that a person on the equator would weight 3/5th as much as present..??
2 answers
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