To find the value of b, we can use the fact that the sum of the solutions for a quadratic equation is equal to the negation of the linear coefficient (b) divided by the leading coefficient (1 in this case).
The sum of the solutions is -11 + 5 = -6.
So, we have:
-6 = -b/1
Solving for b, we get:
b = 6
Therefore, the value of b that makes the solutions -11 and 5 is 6.
What should be the value of b in x2+bx−55=0 so that its solutions are −11 and 5? (1 point) Responses −6 negative 6 6 6 −16 negative 16 16 16
1 answer
1 answer