What should be the value of b in x2+bx−55=0 so that its solutions are −11 and 5?

Answer 1

To find the value of b, we can use the fact that the sum of the roots of a quadratic equation is equal to the opposite of the coefficient of the linear term divided by the coefficient of the quadratic term.

In this case, the sum of the roots is -11 + 5 = -6. So, we have:

-6 = -b/1

Multiplying both sides of the equation by 1, we get:

b = 6

Thus, the value of b should be 6.