To find the value of b, we can use the fact that the sum of the roots of a quadratic equation is equal to the negation of the coefficient of the linear term divided by the coefficient of the quadratic term.
In this equation, the quadratic term coefficient is 1 and the linear term coefficient is b. Therefore, the sum of the roots is -b/1. The sum of the roots in this case is -11 + 5 = -6.
Therefore, we have -b/1 = -6.
To solve for b, we can multiply both sides of the equation by 1 to eliminate the denominator:
-b = -6.
Since we want the value of b, we can multiply both sides of the equation by -1:
b = 6.
So, the value of b is 6.
What should be the value of b in x2+bx−55=0 so that its solutions are −11 and 5? (1 point) Responses −6 negative 6 6 6 16 16 −16
1 answer
1 answer