To find the value of b in the quadratic equation x^2 + bx - 55 = 0 such that its solutions are -11 and 5, we can use the fact that in a quadratic equation of the form ax^2 + bx + c = 0, the sum of the solutions is -b/a and the product of the solutions is c/a.
In this case, the sum of the solutions is -11 + 5 = -6 and the product of the solutions is (-11)(5) = -55.
So we have -6 = -b/1 and -55 = -55/1.
Simplifying the equations, we get -6 = -b and -55 = -55.
Therefore, the value of b that satisfies these equations is b = 6.
what should be the value of b in x^2+bx-55=0 so that its solutions are -11 and 5
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