what should be the resistance of a heating coil which will be used to raise the temperature of 500 grams of water from 28 degrees celcius to 100 degrees celcius in 2 minutes, assuming that 25% of the heat is lost? the heater utilizes 110 volts.

Answer 1

Boiling point=100C
Heat gained=specific heatxmassxtemperature rise
Heat gained=(1000cal/kg.Cx0.5kgx(100C+28C)(0.75)
Heat gained=48000cal
P=48000cal/120s
P=400cal/s=1673.64W
P=V^2/R
1673.64W=(110V)2/R
R=7.23ohms

Answer 2

Boiling point=100C
Heat gained=specific heatxmassxtemperature rise
Heat gained=(1000cal/kg.Cx0.5kgx(100C+28C)(0.75)
Heat gained=48000cal
P=48000cal/120s
P=400cal/s=1673.64W
P=V^2/R
1673.64W=(110V)^2/R
R=7.23ohms

Answer 3

When can the final temperature be added to the initial temperature