What set of quantum numbers n, l,m,ms is invalid

3 answers

An invalid set of quantum numbers would not follow the rules of the allowed values for each quantum number. Here are the general rules:

- The principal quantum number (n) can be any positive integer (1, 2, 3, ...)
- The azimuthal quantum number (l) can be any integer from 0 to (n-1). In other words, l can have values of 0, 1, 2, ..., n-1.
- The magnetic quantum number (m) can have values from -l to +l, including 0.
- The spin quantum number (ms) can either be +1/2 or -1/2.

Using these rules, an invalid set of quantum numbers could be, for example:

- n = 0 (n cannot be zero)
- l = 4, n = 2 (l cannot be greater than or equal to n)
- m = -3, l = 2 (m must be between -l and +l, inclusive)
- ms = 0 (ms must be either +1/2 or -1/2)
a
I'm sorry, could you please provide more context or information so I can assist you better?