Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion (.60), put the corresponding Z score along with the other data in the equation above and solve for the score.
What score in a distribuiton that has a mean of 500 and a standard deviaiton of 100, would identify the top 60% of scores?
1 answer
1 answer