1 mol CH4 x (16 g CH4/1 mole CH4) = ?g CH4
L CH4 x (1 mole CH4/22.4 L) = ? moles CH4
#molecules CH4 x (1 mole/6.022 x 10^23 molecules) = ? moles CH4
The fraction (ratio) in parentheses is the ratio the problem is asking for. You did b right. Note that in my solutions for
a). mole cancels to leave g as the unit.
b). L cancels to leave moles as the unit.
c). # molecules cancel to leave moles as the unit.
What ratio is used to carry out each conversion?
a.mol CH4 to grams CH4
b.L CH4(g) to mol CH4(g)(at STP)
c.molecules CH4 to mol CH4
I honestly don't kno what it's asking me
I got 1 mol CH4/ 16(g) CH4 for a.
1 mol/22.4 L for b.
and 6.02 x 10^23 molecules/1 mol
but I don't think this is right, is it?
4 answers
I don't kno either bro
car
well if Ch4 is is being transferred then you need to.......
idk what im saying lol
idk what im saying lol