what r the 2 main characteristics of a shunt connected motor?
http://www.answers.com/topic/direct-current-motor
sorry cant find what i'm looking for. anything else?
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COMPARE THE STARTING TORQUE OF A SHUNT AND SERIES MOTOR?
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COMPARE THE NO LOAD SPEEDSOF SHUNT AND SERIES CONNECTED MOTORS?
Hmmm. That specifically was in the article. I wonder how you missed it. Series motors are used for high torque applications, shunt motors are used for level load applications. I suggest reread the link I sent you.
sorry don't know how i missed itbut they only give one characteristic i still need another one
what is IT ETT ABOUT
A load draws 10 A of current from a 120-V source. The voltage leads the current by 36.9 degrees. Determine the following:
(a) _________ Resistive current
(b) __________ Reactive current
1 answer
1. Constant speed: Shunt connected motors maintain, almost, a constant speed regardless of the load. This characteristic makes them suitable for applications where constant speed is required, such as lathes, blower fans, and machine tools.
2. High starting torque: Shunt connected motors have relatively high starting torque, which makes them suitable for various industrial applications.
Now, for the comparison of starting torque and no-load speeds between shunt and series connected motors:
Starting Torque:
- Shunt motor: High starting torque
- Series motor: Extremely high starting torque
No-load Speeds:
- Shunt motor: Almost constant speed, regardless of the load
- Series motor: No-load speed is very high and can be dangerously unstable. Hence, they are never operated without a load.
As for the last question:
A load draws 10 A of current from a 120-V source. The voltage leads the current by 36.9 degrees.
We can use the cosine of the angle to find the resistive and reactive currents:
Resistive current (I_R) = I * cos(angle)
Reactive current (I_X) = I * sin(angle)
where I = total current, and the angle = 36.9 degrees
(a) Resistive current:
I_R = 10A * cos(36.9) = 10A * 0.8 = 8 A
(b) Reactive current:
I_X = 10A * sin(36.9) = 10A * 0.6 = 6 A