what r the 2 main characteristics of a shunt connected motor?

Question

http://www.answers.com/topic/direct-current-motor

sorry cant find what i'm looking for. anything else?
------------------AND---------------------

COMPARE THE STARTING TORQUE OF A SHUNT AND SERIES MOTOR?
--------------- & ----------
COMPARE THE NO LOAD SPEEDSOF SHUNT AND SERIES CONNECTED MOTORS?

Hmmm. That specifically was in the article. I wonder how you missed it. Series motors are used for high torque applications, shunt motors are used for level load applications. I suggest reread the link I sent you.

sorry don't know how i missed itbut they only give one characteristic i still need another one

what is IT ETT ABOUT

A load draws 10 A of current from a 120-V source. The voltage leads the current by 36.9 degrees. Determine the following:
(a) _________ Resistive current
(b) __________ Reactive current

Answer 1

The main two characteristics of a shunt connected motor are:

1. Constant speed: Shunt connected motors maintain, almost, a constant speed regardless of the load. This characteristic makes them suitable for applications where constant speed is required, such as lathes, blower fans, and machine tools.

2. High starting torque: Shunt connected motors have relatively high starting torque, which makes them suitable for various industrial applications.

Now, for the comparison of starting torque and no-load speeds between shunt and series connected motors:

Starting Torque:
- Shunt motor: High starting torque
- Series motor: Extremely high starting torque

No-load Speeds:
- Shunt motor: Almost constant speed, regardless of the load
- Series motor: No-load speed is very high and can be dangerously unstable. Hence, they are never operated without a load.

As for the last question:

A load draws 10 A of current from a 120-V source. The voltage leads the current by 36.9 degrees.

We can use the cosine of the angle to find the resistive and reactive currents:

Resistive current (I_R) = I * cos(angle)
Reactive current (I_X) = I * sin(angle)

where I = total current, and the angle = 36.9 degrees

(a) Resistive current:
I_R = 10A * cos(36.9) = 10A * 0.8 = 8 A

(b) Reactive current:
I_X = 10A * sin(36.9) = 10A * 0.6 = 6 A