What pressure (in atmospheres) will be exerted by 1.3 moles of gas in a 13 litre flask at 22 degrees Celcius? (Gas constant (R) = 0.0821 L atm K^-1 mol^-1)

Answer 1

Use ideal gas law:

PV=nRT (T in °K)

=>

P=nRT/V
=1.3 mol *0.0821 L atm °K^-1 mol^-1 *(22+273.16)°K/13 L
=2.423 atm
=2.4 atm (approx.)