Do you mean "at what points does the sin of theta equal zero"?
If so, sin(Theta) = Y/r. Then sine of theta is zero at every point where Y equals zero: 0, 180, and 360o.
What point on the x-y plane does theta = 0 describe?
I tried doing:
tan(theta) = y/x
tan(0rad) = y/x
0 = y/x
So y is definitely 0.
y = rsin(theta)
r = y/sin(theta)
= 0/sin(0rad)
= 0/0
... I highly doubt that this problem was meant for having to do L'Hopital's rule, so I'm not sure what to do here. Thanks for any help in advance.
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