That equals the ratio of the integral of e^-x^2 from 0 to 2 to the integral of e^-x^2 from 0 to infinity. (The curve is symmetric about the y axis, so you only need to do one half of the integration.)
You can find the answer in tables of the probability integral. It is 0.99532
what percent of the area between f(x)=e^-x2 and the x axis is between x=-2 and x =2
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