To express the number 63 in terms of its prime factorization using exponents, we need to break it down into its prime factors.
The prime factorization of 63 is:
\[ 63 = 3^2 \times 7^1 \]
This indicates that 63 can be expressed as:
- The prime factor 3 raised to the power of 2 (which is \(3 \times 3\)).
- The prime factor 7 raised to the power of 1 (which is just \(7\)).
Thus, 63 in exponent form of its prime factors is \(3^2 \times 7^1\).