To find the output for an input of 4 using the rule provided (multiply by 3, then add 1), we can follow these steps:
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Multiply the input (4) by 3: \( 4 \times 3 = 12 \)
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Add 1 to the result: \( 12 + 1 = 13 \)
Therefore, the output is 13.
What number would be output when an input of 4 is evaluated using the rule shown in the image? Enter your response in the output box. (1 point)
Input 4 Rule multiply by 3, then add 1 () output
5 answers
The number of bugs doubles every 4 days. If the bug population starts with 6 bugs, then the equation A(t)=6(2)^0.25t can represent the number of bugs. Find the value for A(8) .(1 point) The number of bugs after 8 days is
To find the value of \( A(8) \) using the equation \( A(t) = 6(2)^{0.25t} \), we will substitute \( t = 8 \) into the equation.
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Substitute \( t = 8 \): \[ A(8) = 6(2)^{0.25 \times 8} \]
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Calculate \( 0.25 \times 8 \): \[ 0.25 \times 8 = 2 \]
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Now replace the exponent in the equation: \[ A(8) = 6(2)^{2} \]
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Calculate \( (2)^{2} \): \[ (2)^{2} = 4 \]
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Now multiply by 6: \[ A(8) = 6 \times 4 = 24 \]
Therefore, the number of bugs after 8 days is 24.
The distance away from the city of Bloomsfield is a function of time. The function D(h)=440−65h represents the distance in miles away from Bloomsfield as you travel toward the city, based on the number of hours, h , you have traveled. Find the distance left to get to Bloomsfield after 3 1/2 hours of traveling. Enter your response in decimal form.(1 point) The distance that you have left to travel is () miles.
To find the distance left to get to Bloomsfield after traveling for \( 3.5 \) hours, we'll substitute \( h = 3.5 \) into the function \( D(h) = 440 - 65h \).
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Substitute \( h = 3.5 \): \[ D(3.5) = 440 - 65 \times 3.5 \]
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Calculate \( 65 \times 3.5 \): \[ 65 \times 3.5 = 227.5 \]
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Now, replace this value back into the equation: \[ D(3.5) = 440 - 227.5 \]
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Perform the subtraction: \[ D(3.5) = 212.5 \]
Therefore, the distance left to travel to get to Bloomsfield after \( 3.5 \) hours is 212.5 miles.