What number exceeds y by 4 less than x?
11 answers
The number that exceeds y by 4 less than x can be expressed as (x - 4).
No.
Apologies for the incorrect response. Let me correct myself.
The correct expression for the number that exceeds y by 4 less than x is (x - 4 - y). In this case, we subtract 4 from x and then subtract y to get the desired number.
The correct expression for the number that exceeds y by 4 less than x is (x - 4 - y). In this case, we subtract 4 from x and then subtract y to get the desired number.
no
I apologize once again. Let me correct my previous response.
The number that exceeds y by 4 less than x can be expressed as (y + (x - 4)). In this expression, we add x minus 4 to y to get the desired number.
The number that exceeds y by 4 less than x can be expressed as (y + (x - 4)). In this expression, we add x minus 4 to y to get the desired number.
There are three consecutive odd integers. Three times the largest is seven times the smallest. What are the integers?
Let's assume that the three consecutive odd integers are x, x+2, and x+4.
According to the problem, three times the largest integer is seven times the smallest integer.
So, we can write the equation as:
3(x+4) = 7x
Simplifying the equation:
3x + 12 = 7x
Subtracting 3x from both sides:
12 = 4x
Dividing both sides by 4:
x = 3
Therefore, the three consecutive odd integers are 3, 5, and 7.
According to the problem, three times the largest integer is seven times the smallest integer.
So, we can write the equation as:
3(x+4) = 7x
Simplifying the equation:
3x + 12 = 7x
Subtracting 3x from both sides:
12 = 4x
Dividing both sides by 4:
x = 3
Therefore, the three consecutive odd integers are 3, 5, and 7.
Separate 90 into two parts so that one part is four times the other number.
Let's assume the two parts that add up to 90 are x and y, where x is four times y.
We can write the equation as:
x + y = 90
Since x is four times y, we can substitute x with 4y:
4y + y = 90
Combining like terms:
5y = 90
Dividing both sides by 5:
y = 18
Now, we can find x by substituting y in the equation:
x + 18 = 90
x = 90 - 18
x = 72
Therefore, the two parts that add up to 90, where one part is four times the other, are 72 and 18.
We can write the equation as:
x + y = 90
Since x is four times y, we can substitute x with 4y:
4y + y = 90
Combining like terms:
5y = 90
Dividing both sides by 5:
y = 18
Now, we can find x by substituting y in the equation:
x + 18 = 90
x = 90 - 18
x = 72
Therefore, the two parts that add up to 90, where one part is four times the other, are 72 and 18.
There is a number. Three times the number minus six is 45. Find the original number.
Let's assume the original number is x.
According to the problem, three times the number minus six is 45. We can write this as an equation:
3x - 6 = 45
To solve for x, we can add 6 to both sides of the equation:
3x - 6 + 6 = 45 + 6
This simplifies to:
3x = 51
Now, we can divide both sides of the equation by 3 to isolate x:
3x/3 = 51/3
This further simplifies to:
x = 17
Therefore, the original number is 17.
According to the problem, three times the number minus six is 45. We can write this as an equation:
3x - 6 = 45
To solve for x, we can add 6 to both sides of the equation:
3x - 6 + 6 = 45 + 6
This simplifies to:
3x = 51
Now, we can divide both sides of the equation by 3 to isolate x:
3x/3 = 51/3
This further simplifies to:
x = 17
Therefore, the original number is 17.
2 answers