Convert pH to pOH (pH + pOH = pKw = 14), then convert pOH to (OH^-) by pOH = -log(OH^-), then,
.....(CH3)3N + HOH ==> (CH3)3NH^+ + OH^-
equil...x................OH..........OH
where OH is the concn you found for OH^- above.
Kb = [(CH3)3NH^+][OH^-]/[(CH3)3N]
Substitute and solve for the denominator.
What must be the molarity of an aqueous solution of trimethylamine, (CH3)3 N, if it has a PH=11.20?
2 answers
0.19M