assuming this particular limestone is purely CaCO3
CaCO3 + HCl
see
https://www.youtube.com/watch?v=PP3o4iQsy7U
CaCO3 mol mass = 40 + 12 + 3(16)
mols reacted = 50/(40+12+3*16)
calculate mols of HCl needed from balanced reaction (twice as many)
mol of HCl has mass 1+35.5
mass needed = mols of HCl needed *(36.5 grams/mol)
What maszid hydrochloric acid is needed to decompose 50g of limestone?
4 answers
Answer is truly correct but more explaination I want. But thanku a lot
The answer is truly correct but more explaination I want
Thanku
Thanku
the answer is absolutely correct but I need more explanation but thank you
1 answer