What mass would you hang on the right side of the system in the figure to balance it -- that is, to make the clockwise and counterclockwise torques equal? (Let x1 = 33 cm and x2 = 12 cm.)
6 answers
I do not know either mass or the x of the right hand side
Sorry! Mass of the weight on the left hand side, hanging from x1 = 50 g
so where is the fulcrum?
The center of the anvil. x1 = 33 cm to the left with a 50 g weight hanging. x2 = 12 cm to the right with a ? weight hanging.
lol, finally
33 * 50 = 12 x
x = 33 * 50/12
33 * 50 = 12 x
x = 33 * 50/12
Thank you!