What mass of Zn can be dissolved by 558 mL of 3.01M HCl?

Answer 1

If I did it correctly is should be 110 g Zn

Answer 2

how do you figure that out?

Answer 3

Here is an example of a stoichiometry problem solved. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html

Answer 4

if you haven't figured it out yet, go from the mL to L then to moles and then grams.

558mL x 1 L/1000mL x 3.01mol/1 L x 65.39 g/1 mol

hope this helps!!!