What mass of Zn can be dissolved by 558 mL of 3.01M HCl?
4 answers
If I did it correctly is should be 110 g Zn
how do you figure that out?
Here is an example of a stoichiometry problem solved. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
http://www.jiskha.com/science/chemistry/stoichiometry.html
if you haven't figured it out yet, go from the mL to L then to moles and then grams.
558mL x 1 L/1000mL x 3.01mol/1 L x 65.39 g/1 mol
hope this helps!!!
558mL x 1 L/1000mL x 3.01mol/1 L x 65.39 g/1 mol
hope this helps!!!