What mass of sucrose (C12H22O11) is needed to make 0.500 L of a 0.200 M solution?

(grams = M x gfm x M; sucrose = 342 g/mol)

1 answer

First, we need to calculate the number of moles of sucrose needed to make the solution:

0.200 moles/L x 0.500 L = 0.100 moles

Next, we can use the formula grams = moles x gfm (molar mass) to calculate the mass of sucrose needed:

grams = 0.100 moles x 342 g/mol = 34.2 g

Therefore, 34.2 grams of sucrose is needed to make 0.500 L of a 0.200 M solution.