What mass of solute is contained in 250 mL of 0.895 M NH4Cl?
I think that this is a molarity question. Molarity = mass of solute/volume of solution in L.
You're right. It is a M question and M = mols/L.
1 mL = 0.001 L so 250 mL * 0.001 L = 0.25 L
Right again. 250 mL = 0.250 L.
0.895 M = X (mass of solute)/ 0.25
and you're right to here. Solve for x = mols NH4Cl. Then to find grams it's grams = mols x molar mass = ?<?b> but since the answer is to be in grams, I was thinking of changing 0.895 M into grams.
You can put all of the work at the beginning into one equation like this to read
mL x M x (molar mass/1000) = grams
Check that and see if you get the same answer.
What mass of solute is contained in 250 mL of 0.895 M NH4Cl?
I think that this is a molarity question. Molarity = mass of solute/volume of solution in L.
1 mL = 0.001 L so 250 mL * 0.001 L = 0.25 L
0.895 M = X (mass of solute)/ 0.25 but since the answer is to be in grams, I was thinking of changing 0.895 M into grams.
So I take the NH4Cl and find out it's molar mass which would come out 53.489 g/mol. Then I would divide 0.895 mol/53.489 g/mol to get 0.0167 (round up to 0.017 g)
Does this work or did I just screw this up majorly?
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