millimols HCOOH = mL x M = approx 65 but you need to do all of these calculations more accurately.
mmols HCOONa = base
pH = pKa + log (base)/(acid)
Substitute and solve for (base) in millimols.
Change to mols, then g = mols x molar mass.
You know mols and molar mass
What mass of solid sodium formate (of MW
68.01) must be added to 115 mL of 0.57 mol/L
formic acid (HCOOH) to make a buffer solution
having a pH of 4.16? Ka = 0.00018 for
HCOOH.
Answer in units of g
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whats the answer?
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