what mass of so2 is produced from the reaction between 31.5g of s8 and 8.65g of o2?

I know how to find the limiting reagents and all but I need a little help knowing how to find the mass of the product.

3 answers

After you know the limiting reagent, convert moles of the limiting reagent to moles of the product (using the cofficients in the balanced equation). Then moles of the product x molar mass = grams.
2H20(l) = 2H2 (g) +O2 (g)

For the above, if 1.50 mg of water is decomposed, what mass of hydrogen is procduced? (1 Mg=10^6g=1 metric ton)?

What is the answer and what is the best way to solve this?
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