What mass of silver nitrate is dissolved in 40.0 mL of a 0.400 M solution of silver nitrate?

Answer 1

40 ml of 0.4M solution contains 0.04*0.4
=0.016 mole of AgNO3.
RMM of AgNO3 = 107.87+14+3*16=169.87
So 0.016*169.87=2.72 g