108 g Ag will be deposited with 96,500 coulombs.
You have how many coulombs?
Coulombs = amperes x seconds
C = 2.6 A x 40 min x (60 sec/1 min) = 6,240 C
So 108 x (6,240/96,500) = g Ag deposited.
what mass of silver is deposited when n current of 2.6A is passed through a solution of silversalt for 40 minutes?
(Ag=108, F=96500C
2 answers
108 x (6,240/96,500)=7