1.67E-27kg*(.0015/9.11E-31) =2.75
so three protons.
What mass of protons would be required to just neutralize the charge of 1.5 g of electrons?
my teacher said .0015kg times 1e-/.00091e-27kg times 1pt/1e- times 1.67262e-27 over 1 p
chem - bobpursley, Tuesday, September 21, 2010 at 6:48pm
That is what I would do also. But I think you ought to know why that is the method.
figure number electrons in 1.5g:
number electrons: .0015kg/9.11E-31
now figure the mass of the same number of protons:
1.67E-27kg*(.0015/9.11E-31)
chem - Sara, Tuesday, September 21, 2010 at 6:50pm
do i add the e-27 and e-31. i forget
chem - bobpursley, Tuesday, September 21, 2010 at 6:56pm
a^b/a^c= a^(b-c)
chem - Sara, Tuesday, September 21, 2010 at 6:59pm
what? sry im not getting this...
chem - Sara, Tuesday, September 21, 2010 at 8:30pm
so i got 8.087535951e20 kg. my anser is suppose to be in grams so would it be 8087.535951e17?
does this sound right/what u got?
thanks
1 answer