What mass of precipitate will form if 1.50L of concentrated Pb(ClO3)2 is mixed with 0.200L of 0.280M of NaI? Assume the reaction is complete

Answer 1

You must assume there is enough Pb(ClO3)2 to use all of the NaI.
Pb(ClO3)2 + 2NaI ==> PbI2 + 2NaClO3
mols NaI = M x L = ?
Convert mols NaI to mols PbI2 using the coefficients in the balanced equation.
Convert mols PbI2 to g. g = mols x molar mass.