What mass of precipitate will be formed when 25 mL of 0.532 M silver nitrate is mixed with 25 mL of 0.333 M NaCl?

Answer 1

This is a limiting reagent problem. You know that because amounts are given for BOTH reactants.
AgNO3 + NaCl ==> AgCl + NaNO3

mols AgNO3 = M x L = approx 0.013 but need that more accurately.
mols NaCl = M x L = ? approx 0.0083

So the amount of AgCl that can be formed from the AgNO3 is 0.01 something and that from the NaCl is 0.008 something. The correct answer is ALWAYS the smaller number.
Use the smaller number and convert to grams AgCl. g AgCl = mols AgCl x molar mass AgCl.