Asked by joseph oreoluwa
                what mass of nitrogen(v)oxide would be obtained by heating 33.3g of lead trioxonitrate(v)
            
            
        Answers
                    Answered by
            DrBob222
            
    You need to learn how to name compounds. I assume nitrogen oxide(v) means N2O5; however, when lead(II) nitrate is heated this is what is produced.
2Pb(NO3)2 ==> 2PbO + O2 + 4NO2
mols Pb(NO3)2 = grams/molar mass = estimated 0.1
For every 2 mols Pb(NO3)2 you get 4 mol NO2 so for estd 0.1 mol Pb(NO3)2 you get estd 0.2 mol NO2.
Then mass NO2 = mols NO2 x molar mass NO2.
Also, there are several names for Pb(NO3)2 but lead trioxonitrate(v) is not one of them.
    
2Pb(NO3)2 ==> 2PbO + O2 + 4NO2
mols Pb(NO3)2 = grams/molar mass = estimated 0.1
For every 2 mols Pb(NO3)2 you get 4 mol NO2 so for estd 0.1 mol Pb(NO3)2 you get estd 0.2 mol NO2.
Then mass NO2 = mols NO2 x molar mass NO2.
Also, there are several names for Pb(NO3)2 but lead trioxonitrate(v) is not one of them.
                    Answered by
            Ahmad
            
    Yes
    
                    Answered by
            Joshua uguru 
            
    I need the final answer
    
                    Answered by
            Gold
            
    I need the final answer for this question
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.