Your reaction equation should be
6Li + N2 = 2 Li3N
59.1 ml at STP is
(59.1*10^-3 l)/(22.4 l/mol)
= 2.64*10^-3 moles of N2.
That will react with 6 times as many moles of Li. Compute the mass of that.
What mass of lithium (in g) is required to react completely with 59.1 mL of gas at STP? given the equation 6Li+N2=2Li3
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1 answer