What mass of limestone (in kg) would be required to completely neutralize a 15.2 billion-liter lake that is 1.9×10−5 M in sulfuric acid and 8.6×10−6 M in nitric acid?

Answer 1

For the sulfuric acid..

moles limestone=moles acid

for the nitric acid,
moles limestone=2*moles nitric acid

I will be happy to check your calculations

Answer 2

5.2*10^5