What mass of lead pb(No3) would be required ti yield 9g of lead pb(No3)2 would be required to yeild 9g of lead pb cl2,on the addition of excess Nacl

1 answer

You should proof read your questions before posting. I assume you are treating the nitrate with NaCl to yield PbCl2 but I need a crystal ball to guess at that.
Pb(NO3)2 + 2NaCl --> PbCl2 + 2NaNO3
mols PbCl2 = 9.4/molar mass PbCl2
mol PbCl2 = 1mol Pb(NO3)2
Now convert mols Pb(NO3)2 to grams; i.e.,
g = mols x molar mass
Post your work if you get tuck.