It is the same amount of iron as in the original oxide.
amountmade=percentFe*45.6kg
now the fractional percent of Fe: 3*55.8/(3*55.8+16*4)
What mass of iron metal can be obtained from the reaction of 45.6kg Iron (III) oxide Fe3O4 with carbon monoxide CO as given in the following equation?
Fe3O4 + 4CO = 3Fe + 4CO2
1 answer
1 answer