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what mass of hematite (fe^2O^3)is required to react with excess carbon and produce 2.845g of iron, if the % yield is 75.369

formula is 2fe^2O^3+3C=4Fe+3CO2

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How many moles is 2.845 g of Fe?

then moles of Fe2O3 must be molesFe/.75369 .

Check my thinking.

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