How many moles is 2.845 g of Fe?
then moles of Fe2O3 must be molesFe/.75369 .
Check my thinking.
what mass of hematite (fe^2O^3)is required to react with excess carbon and produce 2.845g of iron, if the % yield is 75.369
formula is 2fe^2O^3+3C=4Fe+3CO2
1 answer