m = 2 mols/kg solvent
Solve for mols
moles = grams/molar mass
You have mole from above and molar mass, solve for grams.
what mass of ethanol(C2H5OH) will be required to prepare a 2.00m solution in 8.00kg of water?
5 answers
what mass of ethanol(C2H5OH) will be required to prepare a 2.00m solution in 8.00kg of water?
Calculate the volume required to dissolve 11.2 g of CuSO4 to prepare a 0.140M solution
what mass of ethanol will be required to prepare a 2.00m solution of in 8.00kg of water
To calculate the mass of ethanol required to prepare a 2.00 M solution in 8.00 kg of water, we can use the formula:
moles of solute = concentration × volume of solution in liters
We know the concentration (2.00 M), and we can assume a volume of 8.00 L (since the density of water is 1 kg/L).
First, we can calculate the number of moles of solute required:
moles of C2H5OH = 2.00 mol/L × 8.00 L = 16.0 mol
Next, we can use the molar mass of ethanol (46.07 g/mol) to convert the moles of ethanol to grams:
mass of C2H5OH = 16.0 mol × 46.07 g/mol = 737 g
Therefore, we would need 737 grams of ethanol to prepare a 2.00 M solution in 8.00 kg of water.
moles of solute = concentration × volume of solution in liters
We know the concentration (2.00 M), and we can assume a volume of 8.00 L (since the density of water is 1 kg/L).
First, we can calculate the number of moles of solute required:
moles of C2H5OH = 2.00 mol/L × 8.00 L = 16.0 mol
Next, we can use the molar mass of ethanol (46.07 g/mol) to convert the moles of ethanol to grams:
mass of C2H5OH = 16.0 mol × 46.07 g/mol = 737 g
Therefore, we would need 737 grams of ethanol to prepare a 2.00 M solution in 8.00 kg of water.