What mass of Cu(IO3)2 can be formed from 0.690g of CuSO4-5H2O?

Answer 1

Work from CuSO4-5H2O + 2IO3^- => Cu(IO3)2 + SO4^2-
Convert 0.690g to moles => 0.0027mole
Since the equation molar ratio is 1:1 for CuSO4-5H2O & Cu(IO3)2 then the moles of Cu(IO3)2 => 0.0027mole.
Convert 0.0027mole Cu(IO3)2 to grams => (0.0027mole)(413.53g/mole)
=>1.14gms Cu(IO3)2

Answer 2

1.295g