C2H5OH + 3O2 ==> 2CO2 + 3H2O
mols C2H5OH = grams/molar mass = 14.8/0.46 = 0.321
mols CO2 = mols C2H5OH x (2 mols CO2/1 mol C2H5OH) = 0.321 x 2 = 0.642. Then grams CO2 = mols CO2 x molar mass CO2 = ?
The other two parts of the problem are worked the same way. Post your work if you get stuck.
What mass of CO2 could be produced from 14.8 g of C2H5OH? Assume C2H5OH is the limiting reactant.
What mass of O2 would be consumed?
What mass of H2O would be produced?
1 answer