Use PV = nRT and solve for n.
P = (282/760) atm
V = 0.443 L
R = 0.08206 L*atm/mol*K
T = -32+273 = ?K
Solve for n = number of mols. Then
mols = grams/molar mass You know mols and molar mass, solve for grams.
What mass of CH4 is contained in a 443 mL sample of CH4 at −32◦C and 282 torr?
Answer in units of g.
I tried so many times and I don't get it!
1 answer
0 answers