1 m^3 = 100 cm x 100 cm x 100 cm = 1E6 cc = 1E3 L = 1000 L.
Use pv = nRT and solve for n.
You know P, V is 1000 L, R is 0.08206, T is 298
Then n = number of moles = grams/molar mass. You know molar mass is 44 and you know moles, solve for grams. Post your work if you get stuck.
What mass of carbon dioxide is present in 1.00 m3 of dry air at a temperature of 25 ∘C and a pressure of 711 torr ?
1 answer