What mass of calcium bromide is needed to prepare 150.0 mL of a 3.50 M solution? (Assume that the molecular weight of CaBr2 is 200.618 g/mol)
A. 105 g
B. 100.42 g
C. 0.105 g
D. 103.35 g
2 answers
See your MgSO4 problem below. Same process.
ferwrt5y6yu
1 answer