What mass of an NO2 is formed when and NO reacts with 384 g of O2?

Answer 1

2NO+O2>>2NO2

the moles of NO2 will be twice the moles of O2
MolesNO2=384/32

massNO2=molesNO2*(14+32)

All this assumes NO is in excess in the reaction

Answer 2

How many grams of NO are required to react with this amount of O2