2NO+O2>>2NO2
the moles of NO2 will be twice the moles of O2
MolesNO2=384/32
massNO2=molesNO2*(14+32)
All this assumes NO is in excess in the reaction
What mass of an NO2 is formed when and NO reacts with 384 g of O2?
2 answers
How many grams of NO are required to react with this amount of O2