To calculate the mass of aluminum that would absorb 250.0 kJ when it melts at its melting point, we need to use the molar enthalpy of fusion.
Given:
Enthalpy of fusion = 10.71 kJ/mol
Heat absorbed = 250.0 kJ
We know that 1 mole of aluminum will absorb 10.71 kJ of energy during the fusion process.
So, we can set up a proportion to find the number of moles of aluminum:
(10.71 kJ/1 mole) = (250.0 kJ/x moles)
Cross-multiplying the equation, we get:
10.71 kJ * x moles = 250.0 kJ
Simplifying the equation, we find:
x moles = 250.0 kJ / 10.71 kJ
Calculating the moles of aluminum:
x moles ≈ 23.34 moles
Since 1 mole of aluminum has a molar mass of 26.98 g, we can calculate the mass of aluminum:
Mass = moles × molar mass
Mass = 23.34 moles × 26.98 g/mol
Mass ≈ 629.35 g
Therefore, the mass of aluminum metal that would absorb 250.0 kJ when it melts at its melting point is approximately 629.35 grams.
what mass of aluminum metal would absorb 250.0kj when it melted at its melting point? the molar enthalpy of fusion for aluminum is 10.71kj/mol
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