What mass of AgN03 would you dissolve in water to get 1g of silver?

Answer 1

AgNO2 = 108 + 14 +3(16) = 170 g/mol
Ag = 108 g/mol

so AgNO3 is 108 grams silver/170 grams Agno3

1 gram silver(170 g AgNO3/108 g Ag)
= 1.57 grams

Answer 2

thanks!