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What mass of AgCl will be obtained by adding an excess of HCl to a solution of 0.34 g of AgNO3 ?

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AgNO3 + HCl ==> AgCl + HNO3
mols AgNO3 = grams/molar mass
Using the coefficients in the balanced equation, convert mols AgNO3 to mols AgCl.
Now convert mols AgCl to grams. g = mols x molar mass.

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