What mass in grams of a 0.500 m(molal) solution of sodium acetate, CH3CO2Na, in water would you use to obtain 0.200mol of sodium acetate?

Answer 1

0.5 m solution = 0.5 mol solute/kg solvent.
mol = g/molar mass and molar mass = about 82 g/mol.
0.5 mol = 1/2*82 = about 41
So 41g CH3COONa in 1 kg H2O = total mass of 1041g.

You want 0.2 mol CH3COONa so
1041g x (0.2/0.5) = ? mass solution

Answer 2

416 grams

Answer 3

0.200 mol ch3coona are in 1041/0.5×0.200
= 416.4g solutiob